536 Puzzles: Problem & Solution #2: Dollar and Cents

Published by Fudgy McFarlen on


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A man entered a store and spent one-half of the money that was in his pocket. When he came out he found that he had just as many cents as he had dollars when he went in and half as many dollars as he had cents when he went in. How much money did he have on him when he entered?

a.b = 2[b/2 .a]  where a is dollars and b is cents

100a+b = 2({b/2}*100 + a) 

100a+b = 100b + 2a 

99a = 99b   now since 99 & 98 are relatively prime and there is no offset the solution is 

a=98  &  b=98 

Thus he entered the shop with $99.98

Categories: MathPuzzles

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