A history of the housing mess. When you try to help the poor with socialist policies you always create a mess. It is left as an exercise for the student to prove this.
13=1
13+23=9 = 32
13+23+33=36 = 62
13+23+33+43=100 = 102
13+23+33+43+53=225 = 152
…. 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16….
These are triangular numbers are in bold:
( n(n+1)/2 )2= n2(n+1)2/4
A question I have in my mind is that Fermat’s last theorem states: If an integer n is greater than 2, then the equation an + bn = cn has no solutions in non-zero integers a, b, and c.
But how about a3 + b3 + c3 = d3 … Are there any integer solutions to this? I ask this because geometrically speaking volume is 1 degree of freedom more than area.
33+43+53=63 …. = 152 - 32
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| By N2H | |||||