Pythagorean Triples Solution

The square of the odd number is Hence the sum of two odd squares is divisible by 2 but not by 4; and therefore the sum of two odd squares cannot be a square. Hence of the numbers x, y one is even. If we suppose that y is even, then x and z are both odd.  Both x and z terms in the parenthesis below will be odd and thus the sum and difference will be even Every common divisor of and is a divisor of their difference 2x. Thence, since z and x are relatively prime odd numbers we conclude that 2 is the greatest common divisor of and . Then we see that each of these numbers must be twice a square, so that we may write  Solving for x, y, z yields Using values of a & b you can generate all the integer solutions.

A variant on the above can be done to illustrate the solution technique more   Using the same argument as above but one of the factors on the right hand side has to account for the g.  Since the g can be in either factor there are two solutions that make up the overall solution Matching the previous phrase with this phrase to equate right hand factor terms  —-OR—-    —-OR—-  Example Solutions with g=2 a=4 b=1 x y z Equation Set 2 4 6  7 4 9  Categories: Math