Cube Sequences

13=1 13+23=9  = 32                          13+23+33=36 = 62 13+23+33+43=100 = 102 13+23+33+43+53=225 = 152 …. 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16…. These are triangular numbers are in bold:  1+2 =3 1+2+3=6 1+2+3+4=10           ( n(n+1)/2 )2= n2(n+1)2/4 A question I have in my mind is that Fermat’s last theorem states: If an integer n is greater than Read more…